Curtis Greenwood
Corryong Cup 2025 · Task 2 (Floater) (Wed, 8 Jan 2025) · floater · ranked #7 · times in Australia/Melbourne (GMT+11)
Scores computed
Landed out at 16.4 km — 418.3 points
The flight
What the tracklog shows, and which crossings scored.
Start time taken: the start gate — the speed-section clock runs from the gate, not from the crossing (FAI S7F §8.3.1).12:30:00
Day quality — points on offer
Task validity 100% of a perfect day, so 1000 of 1000 points were available.
Launch validity — did enough registered pilots launch?100%
Distance validity — did the field fly far enough relative to the nominal distance?100%
Time validity — was the winning time long enough relative to the nominal time?100%
Points on offer for the day1000 pts
1000 × 1.00 × 1.00 × 1.00 = 1000
Split between the components by the goal ratio
distance 479.6 · time 364.3 · leading 91.1 · arrival 65
Distance points
372.1 ptsScored distance16.4 km
Measured along the optimized task line, up to the furthest point on course.
Best distance in class28.6 km
Linear half — half the available points scale with your share of the best distance137 pts
0.5 × (16.36 km ÷ 28.63 km) × 479.6 = 137
Difficulty half — rewards flying past stretches where many pilots landed235.1 pts
The difficulty curve is built from where the whole field landed out (FAI S7F §11.1.1).
Time points
0 ptsTime points are only awarded to pilots who reach the end of the speed section.
Leading points
46.1 ptsLeading points reward flying out front during the speed section — the pilot with the best leading coefficient takes all available leading points, others fall off with the gap.46.1 pts
Measured with the classic squared-distance leading coefficient (S7F §11.3.1, the hang-gliding / GAP2016–2018 variant).
Arrival points
0 ptsArrival points reward crossing the end of the speed section early relative to the other pilots who reached it.0 pts
Total
418.3 ptsDistance + time + leading + arrival, minus penalties418.3 pts
372.1 + 0.0 + 46.1 ≈ 418.3 — the points above are shown rounded to 0.1; the total is rounded from their exact sum.