Craig Taylor
Corryong Cup 2026 (Sample) · Task 2 (Open) (Tue, 6 Jan 2026) · open · ranked #5 · times in Australia/Melbourne (GMT+11)
Scores computed
Made goal in 1:25:27 — 852.4 points
The flight
What the tracklog shows, and which crossings scored.
Crossed the start cylinder boundary 7 times. The scored start is the latest crossing from which the flight still makes its best run along the course — re-starting supersedes an earlier start, while simply flying back through the cylinder later in the task changes nothing.
Start time taken: gate 5 of 7 — the last start gate at or before the crossing. The speed-section clock runs from the gate, not from the crossing (FAI S7F §8.3.1).15:30:00
Completed the task — full task distance is credited.
Day quality — points on offer
Task validity 97% of a perfect day, so 968 of 1000 points were available.
Launch validity — did enough registered pilots launch?100%
Distance validity — did the field fly far enough relative to the nominal distance?100%
Time validity — was the winning time long enough relative to the nominal time?97%
Points on offer for the day968.3 pts
1000 × 1.00 × 1.00 × 0.97 = 968
Split between the components by the goal ratio
distance 355 · time 613
Distance points
355 ptsScored distance67.5 km
Measured along the optimized task line, up to the furthest point on course.
Best distance in class67.5 km
Made goal — full available distance points.355 pts
Time points
497.4 ptsYour speed section time1:25:27
Timed from your 15:30:00 start gate to the end of the speed section (FAI S7F §8.7) — you crossed the start at 15:34:15.
Fastest time in class1:16:17
Time points fall off with the gap to the fastest time497.4 pts
speed fraction = max(0, 1 − ((T − Tbest) ÷ √Tbest)^5⁄6) = 0.811; × 613 available = 497.4 (times in hours)
Total
852.4 ptsDistance + time + leading + arrival, minus penalties852.4 pts
round(355.0 + 497.4, 1 dp) = 852.4