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Gordon Rigg

Corryong Cup 2025 · Task 4 (Open) (Sat, 11 Jan 2025) · open · ranked #7 · times in Australia/Melbourne (GMT+11)

Scores computed

Made goal in 1:13:12 — 769.2 points

The flight

What the tracklog shows, and which crossings scored.

Crossed the start cylinder boundary 7 times. The scored start is the latest crossing from which the flight still makes its best run along the course — re-starting supersedes an earlier start, while simply flying back through the cylinder later in the task changes nothing.
Start time taken: gate 4 of 6 — the last start gate at or before the crossing. The speed-section clock runs from the gate, not from the crossing (FAI S7F §8.3.1).13:00:00
Completed the task — full task distance is credited.

Day quality — points on offer

Task validity 89.58% of a perfect day, so 895.8 of 1000 points were available.

Launch validity — did enough registered pilots launch?100%
Distance validity — did the field fly far enough relative to the nominal distance?100%
Time validity — was the winning time long enough relative to the nominal time?89.58%
Points on offer for the day895.8 pts

1000 × 1.00 × 1.00 × 0.8958 = 895.8

Split between the components by the goal ratio

distance 332.2 · time 563.7

Distance points

332.2 pts
Scored distance58.4 km

Measured along the optimized task line, up to the furthest point on course.

Best distance in class58.4 km
Made goal — full available distance points.332.2 pts

Time points

437 pts
Time points use the 5⁄6 speed-fraction exponent (the current FAI S7F, S7F §11.2).
Your speed section time1:13:12

Timed from your 13:00:00 start gate to the end of the speed section (FAI S7F §8.7) — you crossed the start at 13:02:18.

Fastest time in class (among pilots who made goal)1:02:57
Time points fall off with the gap to the fastest time437 pts

speed fraction = max(0, 1 − ((T − Tbest) ÷ √Tbest)^5⁄6) = 0.7753; × 563.7 available = 437 (times in hours)

Total

769.2 pts
Distance + time + leading + arrival, minus penalties769.2 pts

round(332.2 + 437.0, 1 dp) = 769.2