Troy Horton
Corryong Cup 2025 · Task 1 (Open) (Sun, 5 Jan 2025) · open · ranked #21 · times in Australia/Melbourne (GMT+11)
Scores computed
Made goal in 1:58:02 — 450.7 points
The flight
What the tracklog shows, and which crossings scored.
Crossed the start cylinder boundary 3 times. The scored start is the latest crossing from which the flight still makes its best run along the course — re-starting supersedes an earlier start, while simply flying back through the cylinder later in the task changes nothing.
Start time taken: gate 2 of 4 — the last start gate at or before the crossing. The speed-section clock runs from the gate, not from the crossing (FAI S7F §8.3.1).13:50:00
Completed the task — full task distance is credited.
Day quality — points on offer
Task validity 90.17% of a perfect day, so 901.7 of 1000 points were available.
Launch validity — did enough registered pilots launch?100%
Distance validity — did the field fly far enough relative to the nominal distance?100%
Time validity — was the winning time long enough relative to the nominal time?90.17%
Points on offer for the day901.7 pts
1000 × 1.00 × 1.00 × 0.9017 = 901.7
Split between the components by the goal ratio
distance 398.5 · time 503.2
Distance points
398.5 ptsScored distance50.4 km
Measured along the optimized task line, up to the furthest point on course.
Best distance in class50.4 km
Made goal — full available distance points.398.5 pts
Time points
52.2 ptsTime points use the 5⁄6 speed-fraction exponent (the current FAI S7F, S7F §11.2).
Your speed section time1:58:02
Timed from your 13:50:00 start gate to the end of the speed section (FAI S7F §8.7) — you crossed the start at 13:50:24.
Fastest time in class (among pilots who made goal)1:03:47
Time points fall off with the gap to the fastest time52.2 pts
speed fraction = max(0, 1 − ((T − Tbest) ÷ √Tbest)^5⁄6) = 0.1037; × 503.2 available = 52.2 (times in hours)
Total
450.7 ptsDistance + time + leading + arrival, minus penalties450.7 pts
round(398.5 + 52.2, 1 dp) = 450.7